79. Linked List Cycle II
Topic :
linked lists
Difficulty :
easy
Problem Link :
problem statement
Given the head
of a linked list, return the node where the cycle begins. If there is no cycle, return null
.
There is a cycle in a linked list if there is some node in the list that can be reached again by continuously following the next
pointer. Internally, pos
is used to denote the index of the node that tail's next
pointer is connected to (0-indexed). It is -1
if there is no cycle. Note that pos
is not passed as a parameter.
Do not modify the linked list.
Example 1:
Input: head = [3,2,0,-4], pos = 1
Output: tail connects to node index 1
Explanation: There is a cycle in the linked list,
where tail connects to the second node.
Example 2:
Input: head = [1,2], pos = 0
Output: tail connects to node index 0
Explanation: There is a cycle in the linked list,
where tail connects to the first node.
Input: head = [1], pos = -1
Output: no cycle
Explanation: There is no cycle in the linked list.
Constraints:
- The number of the nodes in the list is in the range
[0, 104]
. -105 <= Node.val <= 105
pos
is-1
or a valid index in the linked-list.
solution
import java.io.*;
import java.util.*;
class Cycle_In_A_LinkedList_II
{
static class Node{
int data;
Node next;
Node(int data){
this.data=data;
this.next=null;
}
}
static Node detectCycle(Node head) {
if(head==null || head.next==null)
return null;
Node slow=head;
Node fast=head;
while(fast.next!=null && fast.next.next!=null)
{
slow=slow.next;
fast=fast.next.next;
if(slow==fast)
{
slow=head;
while(slow!=fast)
{
slow=slow.next;
fast=fast.next;
}
return fast;
}
}
return null;
}
static void display(Node head){
while(head!=null)
{ System.out.print(head.data+" --> ");
head=head.next;
}
System.out.print("null");
System.out.println();
}
public static void main(String args[]){
Node head=new Node(1);
head.next=new Node(2);
head.next.next=new Node(3);
head.next.next.next=new Node(4);
head.next.next.next.next=head.next.next;
System.out.println("The cycle starts at node " + detectCycle(head).data);
}
}