9. Merge Sorted Array
Topic :
arrays
Difficulty :
easy
Problem Link :
problem statement
You are given two integer arrays nums1
and nums2
, sorted in non-decreasing order, and two integers m
and n
, representing the number of elements in nums1
and nums2
respectively.
Merge nums1
and nums2
into a single array sorted in non-decreasing order.
The final sorted array should not be returned by the function, but instead be stored inside the array nums1
. To accommodate this, nums1
has a length of m + n
, where the first m
elements denote the elements that should be merged and the last n
elements are set to 0
and should be ignored. nums2
has a length of n
.
Example 1:
Input: nums1 = [1,2,3,0,0,0], m = 3, nums2 = [2,5,6], n = 3
Output: [1,2,2,3,5,6]
Explanation: The arrays we are merging are [1,2,3] and [2,5,6].
The result of the merge is [1,2,2,3,5,6] with the underlined elements coming from nums1.
Example 2:
Input: nums1 = [1], m = 1, nums2 = [], n = 0
Output: [1]
Explanation: The arrays we are merging are [1] and [].
The result of the merge is [1].
Example 3:
Input: nums1 = [0], m = 0, nums2 = [1], n = 1
Output: [1]
Explanation: The arrays we are merging are [] and [1].
The result of the merge is [1].
Note that because m = 0, there are no elements in nums1. The 0 is only there to ensure the merge result can fit in nums1.
Constraints:
nums1.length == m + n
nums2.length == n
0 <= m, n <= 200
1 <= m + n <= 200
-109 <= nums1[i], nums2[j] <= 109
solution
// merge two sorted arrays and dont use any extra space //
import java.io.*;
import java.util.*;
class Merge_Two_Sorted_Arrays
{
static void merge (int a[],int b[])
{
int m=a.length;
int n=b.length;
for(int i=0;i<m;i++)
{ if (a[i]>b[0])
{ int temp=a[i];
a[i]=b[0];
b[0]=temp;
int first=b[0];
int k;
for ( k=1;k<n && b[k]<first;k++) // sorting the second array back in order
{ b[k-1]=b[k];
}
b[k-1]=first;
}
}
}
public static void main(String args[])
{
int a[]={1,4,7,8,10};
int b[]={2,3,9};
merge(a,b);
for(int i=0;i<a.length;i++)
System.out.print(a[i]+" ");
for(int i=0;i<b.length;i++)
System.out.print(b[i]+" ");
}
}